Solution: count characters with default dict

---

examples/dictionary/count_characters_default_dict.py

from collections import defaultdict

text = """
This is a very long text.
OK, maybe it is not that long after all.
"""

# print(text)
count = defaultdict(int)

for char in text:
    if char == '\n':
        continue
    count[char] += 1

for key in sorted( count.keys() ):
    print("'{}' {}".format(key, count[key]))

• The previous solution can be slightly improved by using defaultdict from the collections module.
• count = defaultdict(int) creates an empty dictionary that has the special feature that if you try to use a key that does not exists, it pretends that it exists and that it has a value 0.
• This allows us to remove the condition checking if the character was already seen and just increment the counter. The first time we encounter a charcter the dictionary will pretend that it was already there with value 0 so everying will work out nicely.