Count words using two vectors

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• Given a string that consists of words and white-spaces, count how many times each word appears!
• In this solution we use two vectors. A much better solution would be to use HashMap, but in this example I wanted to show the solution with two vectors.
• One vector will hold the list of distinct words.
• The second vector will hold the count for each word.

examples/vectors/count-words/src/main.rs

fn main() {
    let text = "mouse cat cat oliphant";
    let parts = text.split_whitespace();

    let mut words:Vec<&str> = vec![];
    let mut count:Vec<i32> = vec![];

    for word in parts {
        let mut found = false;
        for ix in 0..words.len() {
            if words[ix] == word {
                count[ix] += 1;
                found = true;
                break;
            }
        }
        if ! found {
            words.push(word);
            count.push(1);
        }
    }

    // report
    for ix in 0..words.len() {
        println!("{}: {}", words[ix], count[ix])
    }
}

mouse: 1
cat: 2
oliphant: 1