Bash set -e to stop script on failure
Normally if one of the commands executed by a shell script fails it set an exit code different from 0, but the script will not stop. In some cases this might be the proper behavior, but in many cases, especially in a CI system you'll probably want your shell script to fail of one of its commands failed.
The -e tells Bash to stop immediately if one of the statements it executes has an exit-code different from 0.
Every command you run on the command line of Linux has an exit code. 0 indicates success. Any other number is a failure. The variable $? contains the exit-code of the previous command.
E.g. a successful command:
$ ls ... (the content of the directory) $ echo $? 0
A failed command:
$ ls some-place-that-does-not-exist ls: cannot access 'some-place-that': No such file or directory $ echo $? 2
Shell script without -e
In this script we have 3 commands. The 2nd fails, but it does not bother the main script. It keeps working and executes the 3rd command.
#!/bin/bash echo "Start" ls some-incorrect-path echo "Still working"
$ ./examples/shell/no-set-e.sh Start ls: cannot access 'some-incorrect-path': No such file or directory Still working $ echo $? 0
Shell script with -e
We can set the -e either on the sh-bang line or with the set -e command. We can turn it off using the set +e command.
#!/bin/bash -e echo "Start" ls some-incorrect-path echo "Still working"
$ ./examples/shell/set-e.sh Start ls: cannot access 'some-incorrect-path': No such file or directory $ echo $? 2
Here, as you can see, after the 2nd command fails, the whole script stops and the exit-code of the script is set to a non-zero number indicating failure.